Covid-19 and vitamin D

From articles that I have read it appears that lack of sunshine or vitamin D could increase covid-19 infection rates - see https://www.institutefornaturalhealing.com/2020/03/coronavirus-one-vitamin-may-be-the-key-to-stopping-it/ For this reason it could be a good idea to be outside in the sunshine for a portion of the day. As people get older they often suffer from low vitamin D levels. Is it significant that older people are more badly affected by covid-19?
Italy is famous for narrow streets where sunlight does not easily enter. Could this be why Italy was so badly affected?
Covid-19 causes respiratory problems. Is it significant that vitamin D helps prevent respiratory infections - see article mentioned.

Sample code

label 1;
var
T1,Rh1,RH2,T2,T1c,ht,Psat1,Psat2,Pv,Tdew,Psat:extended;
errors1:boolean;
calcstr2,calcstr1:string[30];
begin
errors1:=false;
form4.hide;
form4.show;
{form4.Memo1.clearselection};
try
T1:=strtofloat(form4.edit1.Text);
Rh1:=strtofloat(form4.edit2.Text);
T2:=strtofloat(form4.edit3.Text);
except
errors1:=true;
end;
if (errors1=true) or
(t1<0.01) or (t1>69) or (rh1<0) or (rh1>100) or
(t2<0.1) or (t2>70) or (T2<T1+0.02)
then begin
form4.Memo1.Lines.Add('CHECK ENTRIES.');
goto 1
end;
T1C:=T1;
ht:=1000*(T2-T1)/3.3;
RH1:=RH1/100;
Psat1:=0.61121*exp((18.678-T1/234.5)*T1/(257.14+T1));
Pv:=Psat1*RH1;
Psat2:=0.61121*exp((18.678-T2/234.5)*T2/(257.14+T2));
Rh2:=Pv/Psat2;  {ie partial pressure of water vapour/psat2}
str(rh2*100:9:2,calcstr1);
form4.Memo1.lines.Add('Final relative humidity (at T2) is: '+calcstr1+'%.');
Tdew:=T1;
repeat
Tdew:=Tdew-0.001;
Psat:=0.61121*exp((18.678-Tdew/234.5)*Tdew/(257.14+Tdew));
until (Psat<=Pv);
str(Tdew:12:2,calcstr2);
form4.Memo1.Lines.Add('Dew point is: '+calcstr2+' deg C.');
1: end;

Problems with renewable energy

https://wattsupwiththat.com/2018/12/23/solar-panel-waste-a-disposal-problem/ says:
 "Solar photovoltaic panels, whose operating life is 20 to 30 years, lose productivity over time. The International Renewable Energy Agency estimated that there were about 250,000 metric tons of solar panel waste in the world at the end of 2016 and that this figure would definitely increase. Solar panels contain lead, cadmium, and other toxic chemicals that cannot be removed without breaking apart the entire panel. 3

In November 2016, Japan’s Environment Ministry issued a warning that the amount of solar panel waste Japan produces each year is likely to increase from 10,000 to 800,000 tons by 2040, and the country has no plan for safely disposing of it. 4 A recent report found that it would take 19 years for Toshiba Environmental Solutions to finish recycling all of the solar waste Japan produced by 2020. By 2034, the annual waste production will be 70 to 80 time larger than that of 2020. "

https://fee.org/articles/solar-panels-produce-tons-of-toxic-waste-literally/ says:
"More disconcerting, however, is the environmental impact of these chemicals. Based on installed capacity and power-related weight, we can estimate that by 2016, photovoltaics had spread about 11,000 tons of lead and about 800 tons of cadmium. A hazard summary of cadmium compounds produced by the EPA points out that exposure to cadmium can lead to serious lung irritation and long-lasting impairment of pulmonary functions. Exposure to lead hardly needs further explanation."
https://theconversation.com/theres-a-looming-waste-crisis-from-australias-solar-energy-boom-117421 says:
"Solar panels generally last about 20 years. And lead-acid and lithium-ion batteries, which will be the most common battery storage for solar, last between five and 15 years. Many solar panels have already been retired, but battery waste will start to emerge more significantly in 2025. By 2050 the projected amount of waste from retired solar panels in Australia is over 1,500 kilotonnes (kT)." and

"Given Australia is struggling to recycle simple waste, such as cardboard and plastics, in a cost-effective way, we need to question our capability to deal with more complex solar PV and battery waste.
Australia currently has little capacity to recycle both solar panelsand batteries."
https://quillette.com/2019/02/27/why-renewables-cant-save-the-planet/ says:
"Consider California. Between 2011–17 the cost of solar panels declined about 75 percent, and yet our electricity prices rose five times more than they did in the rest of the U.S. It’s the same story in Germany, the world leader in solar and wind energy. Its electricity prices increased 50 percent between 2006–17, as it scaled up renewables."
https://www.renewableenergyworld.com/2019/04/02/why-100-renewable-energy-goals-are-not-practical-policies/#gref says: "The issue is that our current technologies are intermittent, variable, and unpredictable as they depend on the weather and consequently have limited capacity factors. At the scale needed, storage is currently not a viable option as the technology is very expensive and still developing."

https://www.investors.com/politics/commentary/renewable-energy-possible-good-environment/ says: "There's another problem with renewable energy that environmentalists and politicians tend to overlook when pushing their 100% renewable plans.

Most forms of "clean" energy require massive amounts of land to produce relatively small amounts of energy."

Facebook Profile and Other Sites

My Facebook profile is at https://www.facebook.com/profile.php
For other sites of mine see https://temsites.blogspot.com

Cheap Energy for Africa with Carbon Dioxide Reduction

For reliable renewable energy one needs costly batteries for steady supply and it seems unlikely we will be able to afford sufficient supplies of batteries in the near future. Here is the only solution I can see: 
1) Allow mines to install their own gas turbine power stations so mines can operate well and cheaply all the time
2) Encourage gas and oil companies to set up in South Africa, but legislate that they must distribute alkaline rock dust (from alkaline mine tailings, etc), to react with carbon dioxide and remove it from the atmosphere.
3) Also allow smelters to set up their own gas turbine power stations so that aluminium smelters, etc, can operate well all the time.
Africa and other regions need reliable power and it is unlikely that greenhouse gas concentrations will be reduced. The world could use gas and also alkaline rock to remove carbon dioxide in general from the air and the carbon dioxide created by burning the gas. We could cool Earth like this.
Taking CO2 out of the air: Here is some mathematics for all: Basalt has a density of about 3 tonnes per cubic metre.
A 1 mm thick layer of basalt spread over an area of 1 square km has a volume of (1/1000)x(1000)x(1000) = 1000 cubic metres.
Mass of 1 mm thick basalt layer on 1 square km = volumexdensity = (1000 cubic metres)x(3 tonnes per cubic metre) =3000 tonnes.
1 tonne of basalt can react with about 0.3 tonnes of CO2.
Therefore 3000 tones of basalt can react with about 3000x0.3 = 900 tonnes of CO2.
In a cubic metre of air in a polluted city there could be about 900 tonnes of CO2 in a cubic km.
Conclusion: A 1 mm thick layer of basalt could take out all the CO2 for a km above the basalt layer. Powdered basalt should be used to make the reaction thousands of times faster.

See https://insideclimatenews.org/news/20022018/global-warming-solutions-carbon-storage-farm-soil-crushed-volcanic-rock-research? and

https://arstechnica.com/science/2018/02/spreading-crushed-rock-on-farms-could-improve-soil-and-lower-co₂/ and

https://gulfnews.com/world/gulf/oman/oman-rocks-to-help-fight-global-warming-1.1810841 and

https://arctic-news.blogspot.com/2016/07/olivine-weathering-to-capture-co2-and-counter-climate-change.html?

Lift for a balloon by adding water vapour

Example: Surrounding air is at 25 deg C and RH=60% and P=100 kPa.
A cubic metre of the surrounding air has 1.6 kg of water evaporated into it and ends up at 95 deg C (so the system is a cubic metre of air at 25 deg C and 1.6 kg of water both heated to 95 deg C). The buoyancy of 1 cubic metre of this hot expanded air is now 0.462 kg. The RH is now 82.03% (after water added and heated). With no water added but surrounding air heated to 95 deg C the RH would be 2.25% and the buoyancy would be 0.221 kg.

Here is some computer code that will work out the details for you - I wrote it is Delphi. 

Inputs are Tair1 (temperature of surrounding air in deg C), 

RH1 (relative humidity of surrounding air (percent), 

P (atmospheric pressure in kPa, 

Tair2 (temperature to which air and water will be heated to become moist air), 

ng (number of grams of water that will be heated with 1 cubic metre of surrounding air to Tair2).

Delphi code is below:

label 1;

var

HR1,HR2,Tk1,Tk2,Tair1,RH1,RH2,P,Tair2,ng,Psatv1,Psatv2,Pv1,Pv2,Mv1,Ma1,Mv2,Ma2,

denss,densp,F,a,Dair1,Dair2,Psati,Enth1,Enth2,Enth2m1,Tav,Enthv,Enthvkg,mf1,mf2:extended;

errors1:boolean;

calcstr1,calcstr2,calcstr3,calcstr4,calcstr5,calcstr6,calcstr7,calcstr8,

calcstr9,calcstr10,calcstr11,calcstr12,calcstr13,calcstr14,calcstr15,calcstr16,

calcstr17,calcstr18,calcstr19,calcstr20:string[30];

begin

errors1:=false;

form20.hide;

form20.show;

try

Tair1:=strtofloat(form20.edit1.Text);

RH1:=strtofloat(form20.edit2.Text);

P:=strtofloat(form20.edit3.Text);

Tair2:=strtofloat(form20.edit4.Text);

ng:=strtofloat(form20.edit5.Text);

except

errors1:=true;

end;

if (errors1=true) or

(Tair1<0.1) or (Tair1>80) or (Rh1<1) or (RH1>100) or (P<50) or (P>150) or (Tair2<0.1) or (Tair2>98)

or (ng<0) or (ng>10000)

then begin

form20.canvas.textout(0,100,'CHECK ENTRIES.');

goto 1

end;

Tk1:=Tair1+273.15;

Tk2:=Tair2+273.15;

Psatv1:=0.61121*exp((18.678-Tair1/234.5)*Tair1/(257.14+Tair1));

Pv1:=Psatv1*RH1/100;

Mv1:=Pv1/(0.4615*Tk1);

Ma1:=(P-Pv1)/(0.287*Tk1);

HR1:=Mv1/Ma1;

HR2:=(Mv1+(ng/1000))/Ma1;

Psatv2:=0.61121*exp((18.678-Tair2/234.5)*Tair2/(257.14+Tair2));

RH2:=(HR2*P)/((0.622+HR2)*Psatv2);

Pv2:=Psatv2*RH2;

Mv2:=Pv2/(0.4615*Tk2);

Ma2:=(P-Pv2)/(0.287*Tk2);

Enth1:=ma1*1.005*Tair1+(ma1)*HR1*(2501.3+1.88*Tair1)+(ng/1000)*4.18*Tair1;

Enth2:=ma1*1.005*Tair2+(ma1)*HR2*(2501.3+1.88*Tair2);

Enth2m1:=Enth2-Enth1;

Dair1:=(Mv1+Ma1);

Dair2:=(Mv2+Ma2);

denss:=Dair1;

Densp:=Dair2;

F:=9.80665*(Denss-densp);

a:=9.80665*((denss/densp)-1);

Tav:=(Tair1+Tair2)/2;

mf1:=Pv1/P;

mf2:=Pv2/P;

Enthv:=2501.3-2.4432443*(Tav-0.01);

Enthvkg:=ng*Enthv/3600;

str(Mv1:12:6,calcstr1);

str(Ma1:12:6,calcstr2);

str(Dair1:12:6,calcstr3);

str(HR1:12:6,calcstr4);

str(Mv2:12:6,calcstr5);

str(Ma2:12:6,calcstr6);

str(Dair2:12:6,calcstr7);

str(HR2:12:6,calcstr8);

str(RH2*100:12:2,calcstr9);

str(F:12:3,calcstr10);

str((F/9.80665):12:3,calcstr11);

str(a:12:3,calcstr12);

str(Enth1:12:3,calcstr13);

str(Enth2:12:3,calcstr14);

str(Enth2m1:12:3,calcstr15);

str(Enth2m1*(1000/3600):12:3,calcstr16);

str(Enthv:12:3,calcstr17);

str(Enthvkg:12:3,calcstr18);

str(mf1:12:3,calcstr19);

str(mf2:12:3,calcstr20);

form20.canvas.textout(0,100,'For surrounding air, mass of vapour Mv1 is: '+calcstr1+' kg/m^3.');

form20.canvas.textout(0,130,'For surrounding air, mass of air Ma1 is: '+calcstr2+' kg/m^3.');

form20.canvas.textout(0,160,'For surrounding air, density of air Dair1 is: '+calcstr3+' kg/m^3.');

form20.canvas.textout(0,190,'For surrounding air, humidity ratio HR1 is: '+calcstr4+' kg/kg.');

form20.canvas.textout(0,230,'For parcel, Mv2 is: '+calcstr5+' kg/m^3.');

form20.canvas.textout(0,260,'For parcel, Ma2 is: '+calcstr6+' kg/m^3.');

form20.canvas.textout(0,290,'For parcel, Dair2 is: '+calcstr7+' kg/m^3.');

form20.canvas.textout(0,320,'For parcel, HR2 is: '+calcstr8+' kg/kg.');

form20.canvas.textout(0,350,'For parcel at Tair2 deg C, relative humidity RH2 after adding water is: '+calcstr9+'%.');

form20.canvas.textout(0,390,'Buoyancy force on a 1 cubic metre parcel of air is: '+calcstr10+' N ('+calcstr11+' kg force).');

form20.canvas.textout(0,420,'Initial acceleration of the parcel of air is: '+calcstr12+' m/(s.s).');

form20.canvas.textout(0,460,'For 1 m^3 Enth1 is: '+calcstr13+' kJ.      Enth2 is: '+calcstr14+' kJ.');

form20.canvas.textout(0,490,'Enthalpy difference for the two situations is Enth2 - Enth1, which is: '+calcstr15+' kJ.');

form20.canvas.textout(0,520,'Enthalpy difference starting with 1000 m^3 is 1000(Enth2 - Enth1) is: '+calcstr16+' kWh.');

form20.canvas.textout(0,550,'Enthalpy of vaporisation at Tav=(Tair1+Tair2)/2 is: '+calcstr17+' kJ/kg.');

form20.canvas.textout(0,580,'Enthalpy of vaporisation at Tav=(Tair1+Tair2)/2 for ng kg is: '+calcstr18+' kWh.');

form20.canvas.textout(0,610,'For surrounding air, mole fraction of water vapour mf1 is: '+calcstr19+' For parcel, mf2 is: '+calcstr20+'.');

1: end;

Amount of basalt to react with CO2 in air

I believe we will need to take CO2, SO2, NOx, etc, out of the air with powdered basalt and other alkaline rocks. You can join my group https://mewe.com/group/5dca2395b0d95521915ec355
Here is Delphi computer code that will calculate approximately how much basalt powder is needed The inputs are T (air temperature in deg C), RH in %, P (atmospheric pressure in kPa - at the coast P is about 101 kPa), ppm (parts per million of CO2 (probably 415 or more parts).
Code is below:
label 1;
var
Dair,Ma,Tk,Mv,Pv,HR,P,RH,T,Psatw,Pdair,PCO2,MCO2,
Dairkg,PercCV,PercVV,ppm,molH2O,molCO2,thirdc,mbthirdc:extended;
errors1:boolean;
calcstr1,calcstr2,calcstr3,calcstr4,calcstr5,calcstr6,calcstr7,
calcstr8,calcstr9,calcstr10,calcstr11,calcstr12,calcstr13:string[30];
begin
errors1:=false;
form21.hide;
form21.show;
try
T:=strtofloat(form21.edit1.Text);
RH:=strtofloat(form21.edit2.Text);
P:=strtofloat(form21.edit3.Text);
ppm:=strtofloat(form21.edit4.Text);
except
errors1:=true;
end;
if (errors1=true) or
(T<0) or (T>70) or (RH<1) or (RH>100) or (P<10) or (P>150) or
(ppm<100) or (ppm>2500)
then begin
form21.canvas.textout(0,100,'CHECK ENTRIES.');
goto 1
end;
Tk:=T+273.15;
Psatw:=0.61121*exp((18.678-T/234.5)*T/(257.14+T));
Pv:=Psatw*RH/100;
Pdair:=(P-Pv);
PCO2:=Pdair*ppm/1000000;
{HR:=0.622*Pv/(P-Pv);}
Mv:=Pv/(0.4615*Tk);
Ma:=(P-Pv)/(0.287*Tk);
MCO2:=PCO2/(0.1889*Tk);
HR:=Mv/Ma;
Dair:=Mv+Ma;
PercCV:=(PCO2/P)*100;
PercVV:=(Pv/P)*100;
molH2O:=Pv/(0.00831447*Tk);
molCO2:=PCO2/(0.00831447*Tk);
thirdc:=MCO2*1000000*(1/3);
mbthirdc:=thirdC*3.33333;
str(Psatw:13:4,calcstr1);
str(Pv:13:4,calcstr2);
str(HR:13:6,calcstr3);
str(Mv*1000:13:3,calcstr4);
str(Ma*1000:13:3,calcstr5);
str(Dair*1000:13:3,calcstr6);
str(MCO2*1000:13:3,calcstr7);
str(MCO2*1000000:13:2,calcstr8);
str(PercCV:13:3,calcstr9);
str(PercVV:13:3,calcstr10);
str(molCO2:13:4,calcstr11);
str(molH2O:13:4,calcstr12);
str(mbthirdc:13:1,calcstr13);
form21.canvas.textout(0,120,'Saturation vapour pressure over water (Psatwater) is: '+calcstr1+' kPa.');
form21.canvas.textout(0,150,'Pv (actual vapour pressure over water) is: '+calcstr2+' kPa.');
form21.canvas.textout(0,180,'HR (humidity ratio over water) is: '+calcstr3+' kg/kg.');
form21.canvas.textout(0,210,'Mass of vapour in one cubic metre is: '+calcstr4+' grams.');
form21.canvas.textout(0,240,'Mass of DRY air in one cubic metre is: '+calcstr5+' grams.');
form21.canvas.textout(0,270,'Density of air (includes water vapour) is: '+calcstr6+' grams per cubic metre.');
form21.canvas.textout(0,300,'Mass of carbon dioxide in one cubic metre is: '+calcstr7+' grams.');
form21.canvas.textout(0,330,'Mass of carbon dioxide in one cubic kilometre is: '+calcstr8+' tonnes.');
form21.canvas.textout(0,360,'Carbon dioxide (volume percent) is: '+calcstr9+'%.');
form21.canvas.textout(0,390,'Water vapour (volume percent) is: '+calcstr10+'%.');
form21.canvas.textout(0,420,'Moles of carbon dioxide in one cubic metre is: '+calcstr11+' mol.');
form21.canvas.textout(0,450,'Moles of water vapour in one cubic metre is: '+calcstr12+' mol.');
form21.canvas.textout(0,480,'Mass of basalt needed to take out a third of the CO2 in one cubic km is: '+calcstr13+' tonnes.');
1: end;

Water from air Delphi2 Code

THE CODE BELOW IS FREEWARE:
T1 is the temperature of the surrounding air in deg C, RH1 is the relative humidity in percent, P1 is the atmospheric pressure in kPa (at sea level it is about 101.325 kPa), T2 is the temperature to which the air will be cooled, V1 is the volume of air you are going to cool in cubic metres. Code below:
label 1;
var
EnthV1MWh,EnthV1kWh,EnthV1,NokgdaV1,Enthd,Psatw1,Psatw2,Tk1,Tk2,Mvpa1,Enth1,Enth2,Ma1,Mv1,HR1,HR2,
Pv1,PV2,T1,RH1,P1,P2,T2,V1,kgDryAir,EdpkgDA,EnthDV,HR1mHR2,HR1mHR2V,kgpkWh,Td,RH,Psat,Pv,Tdew:extended;
errors1:boolean;
calcstr2,calcstr1,calcstr3,calcstr4,calcstr5,calcstr6,calcstr7,
calcstr8,calcstr9,calcstr10,calcstr11,calcstr12,calcstr13,calcstr14,
calcstr15,calcstr16,calcstr17,calcstr18:string[30];
begin
errors1:=false;
form2.hide;
form2.show;
try
T1:=strtofloat(form2.edit1.Text);
RH1:=strtofloat(form2.edit2.Text);
P1:=strtofloat(form2.edit3.Text);
T2:=strtofloat(form2.edit4.Text);
V1:=strtofloat(form2.edit5.Text);
except
errors1:=true;
end;
if (errors1=true) or
(T1<0.1) or (T1>100) or (RH1<0.1) or (RH1>100) or (P1<50) or (P1>150) or (T2<0.1) or
(T2>100) or (V1<0) or (T2>=T1-0.01)
then begin
form2.canvas.textout(0,100,'CHECK ENTRIES.');
goto 1
end;
Tk1:=T1+273.15;
Tk2:=T2+273.15;

Td:=T1;
RH:=RH1;
Psat:=0.61121*exp((18.678-Td/234.5)*Td/(257.14+Td));
Pv:=(RH/100)*Psat;
Tdew:=Td;
repeat
Tdew:=Tdew-0.001;
Psat:=0.61121*exp((18.678-Tdew/234.5)*Tdew/(257.14+Tdew));
until (Psat<=Pv);
str(Tdew:12:2,calcstr18);


Psatw1:=0.61121*exp((18.678-T1/234.5)*T1/(257.14+T1));
Pv1:=Psatw1*RH1/100;
HR1:=0.622*Pv1/(P1-Pv1);
Ma1:=(P1-Pv1)/(0.287*Tk1);
Enth1:=(1.005*T1)+HR1*(2501.3+1.88*T1);
Psatw2:=0.61121*exp((18.678-T2/234.5)*T2/(257.14+T2));
HR2:=Hr1;
P2:=P1;
if (Psatw2<PV1) then begin
Pv2:=Psatw2;
HR2:=0.622*Pv2/(P2-Pv2);
form2.canvas.textout(0,90,'Water condenses out. Dew point is:'+calcstr18+' deg C');
end;
Enth2:=(1.005*T2)+HR2*(2501.3+1.88*T2);
kgDryAir:=V1*Ma1;
EdpkgDA:=(Enth2-Enth1);
EnthDV:=kgDryAir*EdpkgDA;
HR1mHR2:=HR1-HR2;
HR1mHR2V:=kgDryAir*HR1mHR2;
kgpkWh:=(-1)*HR1mHR2V/(EnthDV/3600);
str(Enth1:13:4,calcstr1);
str(Enth2:13:4,calcstr2);
str(EdpkgDA:13:6,calcstr3);
str(Ma1:13:4,calcstr4);
str(kgDryAir,calcstr5);
str(EnthDV,calcstr6);
str((EnthDV/3600),calcstr7);
str((EnthDV/3600000),calcstr8);
str((HR1mHR2*1000):13:4,calcstr9);
str(HR1mHR2V,calcstr10);
str((HR1*1000):13:4,calcstr11);
str((HR2*1000):13:4,calcstr12);
str(EnthV1MWh,calcstr16);
str(kgpkWh:13:4,calcstr17);
form2.canvas.textout(0,120,'Enthalpy1 per kg dry air is: '+calcstr1+' kJ/kg dry air.');
form2.canvas.textout(0,150,'Enthalpy2 per kg dry air is: '+calcstr2+' kJ/kg dry air.');
form2.canvas.textout(0,180,'Enthalpy difference per kg dry air is: '+calcstr3+' kJ/kg dry air.');
form2.canvas.textout(0,210,'Mass of DRY air in one cubic metre of original air is: '+calcstr4+' kg.');
form2.canvas.textout(0,240,'Number of kg of dry air in V1 is: '+calcstr5+' kg.');
form2.canvas.textout(0,270,'FOR VOLUME V1: Heat added to volume V1 of air (Enthalpy difference for volume V1) is: '+calcstr6+' kJ.');
form2.canvas.textout(0,300,'FOR VOLUME V1: Heat added to volume V1 of air is: '+calcstr7+' kWh.');
form2.canvas.textout(0,330,'FOR VOLUME V1: Heat added to volume V1 of air is: '+calcstr8+' MWh.');
form2.canvas.textout(0,370,'HR1 - HR2 g/kg is: '+calcstr9+' grams of water vapour per kg dry air (CONDENSES OUT).');
form2.canvas.textout(0,400,'(HR1 - HR2 kg/kg)x(number of kg dry air in volume V1) is: '+calcstr10+' kg of water (CONDENSES OUT).');
form2.canvas.textout(0,440,'HR1 is: '+calcstr11+' g/kg.');
form2.canvas.textout(0,470,'HR2 is: '+calcstr12+' g/kg.');
form2.canvas.textout(0,520,'SUMMARY. Total mass of water condensing out of the air is: '+calcstr10+' kg.');
form2.canvas.textout(0,550,'SUMMARY: Total heat added to the air is: '+calcstr7+' kWh.');
form2.canvas.textout(0,580,'SUMMARY: kg of water produced per kWh of heat removed from air: '+calcstr17+' kg/kWh.');
form2.canvas.textout(0,610,'SUMMARY: Dew point temperature is: '+calcstr18+' deg C.');
1: end;

Removal of methane from the atmosphere

https://en.wikipedia.org/wiki/Atmospheric_methane#Removal_processes says " Furthermore, in an attempt to absorb the methane that is already being produced from landfills, experiments in which nutrients were added to the soil to allow methanotrophs to thrive have been conducted. These nutrient supplemented landfills have been shown to act as a small scale methane sink, allowing the abundance of methanotrophs to sponge the methane from the air to use as energy, effectively reducing the landfill's emissions." Also says: "Forest soils act as good sinks for atmospheric methane because soils are optimally moist for methanotroph activity, and the movement of gases between soil and atmosphere (soil diffusivity) is high " So forests could be good.

Humidification for rain

This triangular cloth-covered framework device shown will deflect a huge volume of air into the almost saturated layer just above the sea during the course of a day and will facilitate the evaporation of spray above the surface by creating turbulence with the downwards direction of the air. Just before a sea breeze develops (breeze from sea to land) the air that is being warmed on land expands upwards and outwards, keeping the sea breeze from developing. Warm dry air from this expanded volume of air will be mixed, by this device, into the spray and almost-saturated air region just above the sea just before the sea breeze develops. A deeper moist layer will then blow in with the sea breeze, facilitating rain.
If the spray was just rising a few cm without the device and is forced a few m upwards by the wind with the device there will be a big increase in evaporation. If a few cubic km of air per day is directed down by the device you will have a huge amount of moist air. Imagine the device is 1 km long, 1/100 km high and wind blows at 10 km/hour for 20 hours. Then 2 cubic km of air per day could be forced down.
When there is a drought the land gets hotter because of no evaporation (hot deserts are hotter than tropical forests where there is evaporation). When land gets hotter the air above the land gets hotter and then relative humidity of the air drops and the vapour pressure deficit (VPD) increases a lot. From what I have read plants generally like a vapour pressure deficit (VPD) of between 0.8 kPa and 1.2 kPa. This means that the vapour pressure inside the plant minus the vapour pressure in the air should be 0.8 to 1.2 kPa. Failing this there is wilting, etc. Even if you do not get rain it might be worthwhile humidifying the air around the coast or planting more trees

Wetter or drier?

Will the world become wetter or drier overall? The article https://www.aaas.org/news/drying-atmosphere-spurs-decline-vegetation-growth says: "The findings reveal that atmospheric water vapor is expected to further wane throughout the 21st century due to rising air temperatures and a decline in the evaporation of the world's oceans."
People might find it strange that as air temperatures increase the evaporation from oceans decreases, but here is an explanation: When it comes to evaporation from the sea, most evaporation occurs when the sea is hotter than the air above it. With global warming the land heats up more than the sea and so you might tend to get air that is relatively hotter than the sea blowing to sea. When hotter air is above the sea the sea cools the air above and the relative humidity (RH) of this air increases and less evaporation results into the air because RH is higher. When The sea is warmer than the air above it the sea heats the air above it and the RH of the air decreases and more evaporation occurs because RH is low. When you have cold sea near to hot land you can get "negative evaporation" - the water vapour condenses out of the hot air above the cold sea and fog occurs.
One factor that could increase the evaporation is increased downwelling sky radiation from hotter air, but the effect of increasing RH of hotter air above cold water appears to be a clear winner in certain regions at present.
Solution: A stagnant saturated layer builds up just above the sea surface so a sheet along the coast and above the sea that deflects air downwards and gives turbulence could partially solve the problem and increase evaporation. Also see https://journals.ametsoc.org/doi/full/10.1175/JCLI3519.1 
I have been dealing with evaporation equations for a while and I take the average of 5 equations (equations from Fitzgerald, Rohwer, Engineering Toolbox, Horton, Meyer) and here are some results: Suppose wind speed is 10 km per hour, RH=80% above the sea, sea temperature is 18 deg C and atmospheric pressure is 760 mm of mercury.
If we increase the air temperature above the sea we get this. 
Tair= 0 deg C then evaporation is 13 mm per day. 
Tair=10 deg C then evaporation is 9 mm per day. 
Tair= 20 deg C then evaporation is 1 mm per day. 
Tair=30 deg C then fog forms above water.

Cooling cities near the coast

For cities near the coast one could use mirrors to shade the ground and also reflect solar energy to old floating abandoned ships. The old ships will heat up and transfer infrared radiation to the the sea surface. Infrared radiation only penetrates the sea a few mm. This could cause clouds to form to shade and cool and bring rain.  Rising moist hot air from the sea could increase air circulation and reduce air pollution in cities.

Carbon dioxide and drowsy accidents

The world is drifting towards drowsiness and accident-proneness: If one calculates, using equations related to the Keeling Curve, one finds that by 2070 the concentration of carbon dioxide in the atmosphere will be about 700 ppm (at present it is around 400 ppm). By 2095 it will be about 1000 ppm. Now when the concentration becomes 1000 ppm people start to feel drowsy and will lose concentration. 
But another problem is that when atmospheric carbon dioxide levels are high and one enters an enclosure (room and so on) the carbon dioxide levels quickly reach dangerous levels because of breathing. So if there are 10 people in a room of volume 100 cubic metres and atmospheric concentration of carbon dioxide is 400 ppm then it will take about 22 minutes for levels to reach 1000 ppm. If you start with atmospheric levels of carbon dioxide at 700 ppm then it takes only about 11 minutes for levels to reach 1000 ppm.
Fires (which produce carbon dioxide) will become far more dangerous regarding breathing.

Density of breath and surrounding air

The Delphi 2 code (Pascal) below calculates the density of breath and of the surrounding air. If you enter a hollow or lift or tank and so on and your breath is more dense than the surrounding air it will sink and you could surround yourself with air that has a lot of carbon dioxide in. This could happen during heatwave conditions.
The inputs to the program are: Ts (temperature in deg C of the surrounding air, eg 38), RHs (relative humidity of the surrounding air in %, eg 34), P (the atmospheric air pressure in kPa, eg 100), PercO (the percentage of oxygen used up in breathing, eg 25), Tbr (the temperature of the breath in deg C, eg 37). The Delph1 2 code is below:
label 1;
var
PvBr,Mas,Mvs,Pvs,Psatws,PercO,Ts,Tsk,P,RHs,Tbr,Tbrk,Psatwbr,Denssa,Densbr,a,molDaBr,
MolNBr,MolOBri,MolOBrf,molCO2Bri,molCO2Brf,MolVBr,MolArBr,MolNeBr,MolHeBr,Mol,
MolKrBr,MolXeBr,VN,VO,VCO2,VV,VArg,VNe,VHe,VKr,VXe,MNbr,MOBrf,MCO2brf,MVBr,
MArBr,MNeBr,MHeBr,MKrBr,MXeBr,MBr,VolBr,TDI,Td,RHDI,DI,Pw,Tw,Aw,Bw,RHSw,Psat,
Tdew,Pvd,RH,LCL:extended;
errors1:boolean;
calcstr2,calcstr1,calcstr3,calcstr4,calcstr5,calcstr6,calcstr7,
calcstr8,calcstr9,calcstr10,calcstr11,calcstr12,calcstr13,calcstr14,calcstr15,calcstr16,
calcstr17,calcstr18,calcstr19,calcstr20,calcstr21,calcstr22,calcstr23,calcstr24:string[30];
begin
errors1:=false;
form16.hide;
form16.show;
try
Ts:=strtofloat(form16.edit1.Text);
RHs:=strtofloat(form16.edit2.Text);
P:=strtofloat(form16.edit3.Text);
PercO:=strtofloat(form16.edit4.Text);
Tbr:=strtofloat(form16.edit5.Text);
except
errors1:=true;
end;
if (errors1=true) or
(Ts<0) or (Ts>70) or (RHs<=0) or (RHs>100) or (P<10) or (P>150) or(percO<0) or (percO>90)
or (Tbr<0) or (Tbr>70) then begin
form16.canvas.textout(0,100,'CHECK ENTRIES.');
goto 1
end;
Tsk:=Ts+273.15;
Tbrk:=Tbr+273.15;
Psatws:=0.61121*exp((18.678-Ts/234.5)*Ts/(257.14+Ts));
Psatwbr:=0.61121*exp((18.678-Tbr/234.5)*Tbr/(257.14+Tbr));
Pvs:=Psatws*RHs/100;
Mvs:=Pvs/(0.4615*Tsk);
Mas:=(P-Pvs)/(0.287*Tsk);
PvBr:=Psatwbr;
molDaBr:=100-(PvBr/P)*100;
MolNBr:=78.03/100*moldaBr;
MolOBri:=20.99/100*molDaBr;
MolOBrf:=MolOBri-(percO/100*molObri);
MolCO2bri:=(0.033/100)*moldaBr;
MolCO2Brf:=molCO2bri+(percO/100*molObri);
molVbr:=100*Pvbr/P;
molArBr:=(0.94/100)*moldabr;
molNeBr:=(0.0015/100)*moldabr;
molHeBr:=(0.000524/100)*moldabr;
molKrBr:=(0.00014/100)*moldabr;
molXeBr:=(0.000006/100)*moldabr;
MNbr:=molNbr*0.028013;
MObrf:=molOBrf*0.031999;
MCO2Brf:=molCO2Brf*0.04401;
MVBr:=molVBr*0.018015;
MArBr:=molArBr*0.039948;
MNeBr:=molNeBr*0.020183;
MHeBr:=molHeBr*0.004003;
MKrBr:=molKrBr*0.08380;
MXeBr:=molXeBr*0.13130;
Denssa:=Mvs+Mas;
MBr:=MNbr+MOBrf+MCO2Brf+MVBr+MArBr+MNeBr+MHeBr+MKrBr+MXeBr;
VolBr:=100*0.00831447*Tbrk/P;
DensBr:=MBr/VolBr;
a:=9.80665*((denssa/densbr)-1);
VN:=100*MolNBr*(0.00831447*TBrk/P)/VolBr;
VO:=100*MolOBrf*(0.00831447*TBrk/P)/VolBr;
VCO2:=100*MolCO2Brf*(0.00831447*TBrk/P)/VolBr;
VV:=100*MolVBr*(0.00831447*TBrk/P)/VolBr;
VArg:=100*MolArBr*(0.00831447*TBrk/P)/VolBr;
VNe:=100*MolNeBr*(0.00831447*TBrk/P)/VolBr;
VHe:=100*MolHeBr*(0.00831447*TBrk/P)/VolBr;
VKr:=100*MolKrBr*(0.00831447*TBrk/P)/VolBr;
VXe:=100*MolXeBr*(0.00831447*TBrk/P)/VolBr;
str(Denssa:13:3,calcstr1);
str(DensBr:13:3,calcstr2);
str(a:13:2,calcstr3);
str(VN:13:4,calcstr4);
str(VO:13:4,calcstr5);
str(VCO2:13:4,calcstr6);
str(VV:13:4,calcstr7);
str(VArg:13:4,calcstr8);
str(VNe:13:4,calcstr9);
str(VHe:13:4,calcstr10);
str(VKr:13:4,calcstr11);
str(VXe:13:4,calcstr12);

form16.canvas.textout(0,100,'SURROUNDING AIR: DENSITY is: '+calcstr1+' kg/m^3.');
form16.canvas.textout(0,130,'BREATH:          DENSITY is: '+calcstr2+' kg/m^3.');
form16.canvas.textout(0,170,'BREATH: ACCELERATION (negative is down and positive is up) is: '+calcstr3+' m/s^2.');
form16.canvas.textout(0,210,'Breath % vol N2: '+calcstr4+'%.');
form16.canvas.textout(0,240,'Breath % vol O2: '+calcstr5+'%.');
form16.canvas.textout(0,270,'Breath % vol CO2: '+calcstr6+'%.');
form16.canvas.textout(0,300,'Breath % vol H20(g): '+calcstr7+'%.');
form16.canvas.textout(0,330,'Breath % vol Ar: '+calcstr8+'%.');
form16.canvas.textout(0,360,'Breath % vol Ne: '+calcstr9+'%.');
form16.canvas.textout(0,390,'Breath % vol He: '+calcstr10+'%.');
form16.canvas.textout(0,420,'Breath % vol Kr: '+calcstr11+'%.');
form16.canvas.textout(0,450,'Breath % vol Xe: '+calcstr12+'%.');
Td:=Ts;
TDI:=Td;
RHDI:=RHs;
DI:= (2*TDI) + (RHDI/100*TDI)+24;
Pw:=P/101.325;
Tw:=Td;
repeat
Tw:=Tw-0.001;
 Aw:=611.2*exp(17.502*Tw/(240.97+Tw))-66.8745*(1+0.00115*Tw)*Pw*(Td-Tw);
Bw:=6.112*exp(17.502*Td/(240.97+Td));
RHSw:=Aw/Bw;
until (RHSw<=rhs);
RH:=RHs;
Tdew:=Td;
Psat:=0.61121*exp((18.678-Td/234.5)*Td/(257.14+Td));
Pvd:=(RH/100)*Psat;
repeat
Tdew:=Tdew-0.001;
Psat:=0.61121*exp((18.678-Tdew/234.5)*Tdew/(257.14+Tdew));
until (Psat<=Pvd);
LCL:=125*(Td-Tdew);
str(DI:13:1,calcstr13);
str(Tw:13:2,calcstr14);
str(Tdew:13:2,calcstr15);
str(LCL:13:2,calcstr16);
form16.canvas.textout(0,490,'Discomfort Index: '+calcstr13+' (90 to 100 very uncomfortable, 100 to 110 extremely uncomfortable, >110 hazardous).');
form16.canvas.textout(0,520,'Wet Bulb T: '+calcstr14+' deg C');
form16.canvas.textout(0,550,'Dew point: '+calcstr15+' deg C.');
form16.canvas.textout(0,580,'LCL: '+calcstr16+' m.');

1: end;